...MS组内=47.057/5.017=9.380以v1(即组间自由度)=3,v2(即组内自由度)=28查附表19-2,F界值表,得F0.05(3,28)=2.95,F0.01(3,28)=4.57。本例算得的F=9.380>F0.01(...
...V2(较小均方的自由度)V1(较大均方的自由度)123456781224∞...
...V2(较小均方的自由度)V1(较大均方的自由度)123456781224∞...
...4.87,P<0.01;推断区组间的差别,按v1=7,v2=21查F界值表,得F0.05(7,21)=2.49,F0.01(7,21)=3.64,P<0.01。按α=0.05检验水准皆拒绝H0,接受H1,可认为放置时间长短会影响血糖浓度且不同...
.../3=47.057MS组内=SS组内/v组内=140.465/28=5.017F=MS组间/MS组内=47.057/5.017=9.380以v1(即组间自由度)=3,v2(即组内自由度)=28查附表19-2,F界值表,得F0.05(3,28...
...10001.851.811.771.741.721.661.611.571.541.501.431.381.281.191.111000 ∞1.831.791.761.721.701.641.591.551.521.471.401.361.251.151.00∞ 附表9 q值表上行:P=0.05 下行:P=0.01 n'a(组数) 2345678910 ...
...10001.851.811.771.741.721.661.611.571.541.501.431.381.281.191.111000 ∞1.831.791.761.721.701.641.591.551.521.471.401.361.251.151.00∞ 附表9 q值表上行:P=0.05 下行:P=0.01 n'a(组数) 2345678910 ...
...q界值表中自由度一栏无28,可用近似值30或用内插法得出q界值,本例用近似值30查表,当a=4时,q0.05(30,4)=3.85,q0.01(30,4)=4.80,余类推。第(7)栏是按表19-13判定的。4.结论由表19-14可见,除...
...求得(2)用上述的最小显著性差数与每两组均数的相差数比,若后者大于前者(临界值),便相差显著,若小于前者,为相差不显著。现将两均数间的比较结果列于下表。表8.3 均数间两两比较A与B(批号)∣XA-XB∣界 值P值D0.05D0.01 1与...
...(上行:P=0.05,下行:P=0.01)V组 数,a...
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